反常积分的问题dx/(e^(x+1)+e^(3-x))求其1到正无穷大的反常积分就是这个积分,答案是上下同除e^(3-x)得出的结果是(π/4)e^(-2)我做的时候是上下同时除以e^(x+1)得出的结果却是(3π/4)*e^(-2)为什么会不
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![反常积分的问题dx/(e^(x+1)+e^(3-x))求其1到正无穷大的反常积分就是这个积分,答案是上下同除e^(3-x)得出的结果是(π/4)e^(-2)我做的时候是上下同时除以e^(x+1)得出的结果却是(3π/4)*e^(-2)为什么会不](/uploads/image/z/3027186-18-6.jpg?t=%E5%8F%8D%E5%B8%B8%E7%A7%AF%E5%88%86%E7%9A%84%E9%97%AE%E9%A2%98dx%2F%28e%5E%28x%2B1%29%2Be%5E%283-x%29%29%E6%B1%82%E5%85%B61%E5%88%B0%E6%AD%A3%E6%97%A0%E7%A9%B7%E5%A4%A7%E7%9A%84%E5%8F%8D%E5%B8%B8%E7%A7%AF%E5%88%86%E5%B0%B1%E6%98%AF%E8%BF%99%E4%B8%AA%E7%A7%AF%E5%88%86%2C%E7%AD%94%E6%A1%88%E6%98%AF%E4%B8%8A%E4%B8%8B%E5%90%8C%E9%99%A4e%5E%283-x%29%E5%BE%97%E5%87%BA%E7%9A%84%E7%BB%93%E6%9E%9C%E6%98%AF%28%CF%80%2F4%29e%5E%28-2%29%E6%88%91%E5%81%9A%E7%9A%84%E6%97%B6%E5%80%99%E6%98%AF%E4%B8%8A%E4%B8%8B%E5%90%8C%E6%97%B6%E9%99%A4%E4%BB%A5e%5E%28x%2B1%29%E5%BE%97%E5%87%BA%E7%9A%84%E7%BB%93%E6%9E%9C%E5%8D%B4%E6%98%AF%283%CF%80%2F4%29%2Ae%5E%28-2%29%E4%B8%BA%E4%BB%80%E4%B9%88%E4%BC%9A%E4%B8%8D)
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