已知cosα=1/7,cos(α-β)=13/14,且0< β <α<π/2cos(π+2α)tan(π-2α)sin(π/2-2α)(1)求 ---------------------------------------- 的值cos(π/2+2α)(2)求角β
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![已知cosα=1/7,cos(α-β)=13/14,且0< β <α<π/2cos(π+2α)tan(π-2α)sin(π/2-2α)(1)求 ---------------------------------------- 的值cos(π/2+2α)(2)求角β](/uploads/image/z/3710084-68-4.jpg?t=%E5%B7%B2%E7%9F%A5cos%CE%B1%3D1%2F7%2Ccos%EF%BC%88%CE%B1-%CE%B2%EF%BC%89%3D13%2F14%2C%E4%B8%940%EF%BC%9C+%CE%B2+%EF%BC%9C%CE%B1%EF%BC%9C%CF%80%2F2cos%28%CF%80%2B2%CE%B1%29tan%28%CF%80-2%CE%B1%29sin%28%CF%80%2F2-2%CE%B1%29%281%29%E6%B1%82+----------------------------------------+%E7%9A%84%E5%80%BCcos%28%CF%80%2F2%2B2%CE%B1%29%282%29%E6%B1%82%E8%A7%92%CE%B2)
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