求该不定积分 ∫ dx /sin^2 (2x+π/4)
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求该不定积分 ∫ dx /sin^2 (2x+π/4)
求该不定积分 ∫ dx /sin^2 (2x+π/4)
求该不定积分 ∫ dx /sin^2 (2x+π/4)
∫ dx/sin²(2x + π/4)
= (1/2)∫ csc²(2x + π/4) d(2x + π/4)
= (- 1/2)cot(2x + π/4) + C
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