证明:(sinx+1) / cosx = (sinx-cosx+1) / (sinx+cosx-1)
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证明:(sinx+1) / cosx = (sinx-cosx+1) / (sinx+cosx-1)
证明:(sinx+1) / cosx = (sinx-cosx+1) / (sinx+cosx-1)
证明:(sinx+1) / cosx = (sinx-cosx+1) / (sinx+cosx-1)
分析:一般这种三角函数证明题可以1.从左证右2.从右证左3.移项证零
这道题我移项证零
证明:把右边的移到左边,通分
[(sinx+1)(sinx+cosx-1)-cosx(sinx-cosx+1)]/cosx(sinx+cosx-1)=0
(即只要证明分母是0就可以了)中括号里的式子处理一下
得到sin²x+sinxcosx+cosx-1-sinxcosx+cos²x-cosx
最后分母sin²x+cos²x-1=0
所以[(sinx+1)(sinx+cosx-1)-cosx(sinx-cosx+1)]/cosx(sinx+cosx-1)=0
得证.
由题知
cosx(sinx-cosx+1)-(sinx+1)(sinx+cosx-1)
=cosxsinx-cosxcosx+cosx-sinxsinx-sinxcosx+sinx-sinx-sinxcosx+sinx
=0
所以成立
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