用韦达定理做1.x^2 -(m+2)x+2m=0有两个根 其中一个根是另一个的两倍 求m2.2x^2+4x-3=0两根为 x1 x2 求x2/x1 + x1/x2 和 (x1-x2)^23.x^2+(2k+1)x+(k-1)=0 有两个不相等的负根 求k的范围4.方程x^2+px+q=0 有两根 x1 ,x
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![用韦达定理做1.x^2 -(m+2)x+2m=0有两个根 其中一个根是另一个的两倍 求m2.2x^2+4x-3=0两根为 x1 x2 求x2/x1 + x1/x2 和 (x1-x2)^23.x^2+(2k+1)x+(k-1)=0 有两个不相等的负根 求k的范围4.方程x^2+px+q=0 有两根 x1 ,x](/uploads/image/z/5918212-28-2.jpg?t=%E7%94%A8%E9%9F%A6%E8%BE%BE%E5%AE%9A%E7%90%86%E5%81%9A1.x%5E2+-%28m%2B2%29x%2B2m%3D0%E6%9C%89%E4%B8%A4%E4%B8%AA%E6%A0%B9+%E5%85%B6%E4%B8%AD%E4%B8%80%E4%B8%AA%E6%A0%B9%E6%98%AF%E5%8F%A6%E4%B8%80%E4%B8%AA%E7%9A%84%E4%B8%A4%E5%80%8D+%E6%B1%82m2.2x%5E2%2B4x-3%3D0%E4%B8%A4%E6%A0%B9%E4%B8%BA+x1+x2+%E6%B1%82x2%2Fx1+%2B+x1%2Fx2+%E5%92%8C+%EF%BC%88x1-x2%EF%BC%89%5E23.x%5E2%2B%282k%2B1%29x%2B%28k-1%29%3D0+%E6%9C%89%E4%B8%A4%E4%B8%AA%E4%B8%8D%E7%9B%B8%E7%AD%89%E7%9A%84%E8%B4%9F%E6%A0%B9+%E6%B1%82k%E7%9A%84%E8%8C%83%E5%9B%B44.%E6%96%B9%E7%A8%8Bx%5E2%2Bpx%2Bq%3D0+%E6%9C%89%E4%B8%A4%E6%A0%B9+x1+%2Cx)
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