高等代数的矩阵解空间和特征值问题a=(a1,a2,.an),b=(b1,b2,.bn)都是n维列向量,其中ai和bi均为非零常数,i=1,2,.n.设矩阵A=a*(b的转置).也就是A等于列向量a乘以行向量b.(1)求矩阵A的秩r(A)(2)求A的平方,A
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 10:02:17
![高等代数的矩阵解空间和特征值问题a=(a1,a2,.an),b=(b1,b2,.bn)都是n维列向量,其中ai和bi均为非零常数,i=1,2,.n.设矩阵A=a*(b的转置).也就是A等于列向量a乘以行向量b.(1)求矩阵A的秩r(A)(2)求A的平方,A](/uploads/image/z/8752865-41-5.jpg?t=%E9%AB%98%E7%AD%89%E4%BB%A3%E6%95%B0%E7%9A%84%E7%9F%A9%E9%98%B5%E8%A7%A3%E7%A9%BA%E9%97%B4%E5%92%8C%E7%89%B9%E5%BE%81%E5%80%BC%E9%97%AE%E9%A2%98a%3D%28a1%2Ca2%2C.an%29%2Cb%3D%28b1%2Cb2%2C.bn%29%E9%83%BD%E6%98%AFn%E7%BB%B4%E5%88%97%E5%90%91%E9%87%8F%2C%E5%85%B6%E4%B8%ADai%E5%92%8Cbi%E5%9D%87%E4%B8%BA%E9%9D%9E%E9%9B%B6%E5%B8%B8%E6%95%B0%2Ci%3D1%2C2%2C.n.%E8%AE%BE%E7%9F%A9%E9%98%B5A%3Da%2A%28b%E7%9A%84%E8%BD%AC%E7%BD%AE%29.%E4%B9%9F%E5%B0%B1%E6%98%AFA%E7%AD%89%E4%BA%8E%E5%88%97%E5%90%91%E9%87%8Fa%E4%B9%98%E4%BB%A5%E8%A1%8C%E5%90%91%E9%87%8Fb.%EF%BC%881%EF%BC%89%E6%B1%82%E7%9F%A9%E9%98%B5A%E7%9A%84%E7%A7%A9r%28A%29%282%29%E6%B1%82A%E7%9A%84%E5%B9%B3%E6%96%B9%2CA)
xTn@~QP\N+")@8EU=iHۤK+%iJ7/Ix>D4}+ϸB[!e93o$>2|ͳ41+L WٮO,8ja]$fT2Cf4ɼ32BrA*+lC@dr
nP^Ķ!4P%@ck QĀT>Fe쬓`x|\N{;l7VmFmd⚋WThH,
fn )]v$-nqW@dxO#nRU&l:!EPsSǬaޔ: &
Э6`fL2]
&b{A.BH\y=ރ@Hxљ=ZčDKi]m7PsjeU5
Mᖳr
V{@}?WK
_'"k :&rx%l9%RLL!p\Ʈs%^4?٫.Syr`L*2|C${$e
.AiNe;DnEf!)Ȱ#kPnD7D\lG $.-җ