一道高中数学题帮个忙.已知函数f(x)对任意实数a,b有f(a)不等于0,f(a+b)=f(a)f(b),当x小于0时,f(x)大于1.(1)求证:f(x)大于0 (2)求证:f(x)为减函数 (3)当f(4)等于16分之1时,解不等式f(x-3)f(x-5)小于
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![一道高中数学题帮个忙.已知函数f(x)对任意实数a,b有f(a)不等于0,f(a+b)=f(a)f(b),当x小于0时,f(x)大于1.(1)求证:f(x)大于0 (2)求证:f(x)为减函数 (3)当f(4)等于16分之1时,解不等式f(x-3)f(x-5)小于](/uploads/image/z/2791270-46-0.jpg?t=%E4%B8%80%E9%81%93%E9%AB%98%E4%B8%AD%E6%95%B0%E5%AD%A6%E9%A2%98%E5%B8%AE%E4%B8%AA%E5%BF%99.%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0a%2Cb%E6%9C%89f%28a%29%E4%B8%8D%E7%AD%89%E4%BA%8E0%2Cf%28a%2Bb%29%3Df%28a%29f%28b%29%2C%E5%BD%93x%E5%B0%8F%E4%BA%8E0%E6%97%B6%2Cf%28x%29%E5%A4%A7%E4%BA%8E1.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9Af%28x%29%E5%A4%A7%E4%BA%8E0+%282%29%E6%B1%82%E8%AF%81%EF%BC%9Af%EF%BC%88x%29%E4%B8%BA%E5%87%8F%E5%87%BD%E6%95%B0+%EF%BC%883%EF%BC%89%E5%BD%93f%284%29%E7%AD%89%E4%BA%8E16%E5%88%86%E4%B9%8B1%E6%97%B6%2C%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%28x-3%29f%28x-5%29%E5%B0%8F%E4%BA%8E)
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