有这样一个递推公式:2A(n+1)=An+n+3,又告诉A1=2,我想知道由上面的式子怎样推出{An}的通项公式:An=n+1 我自己做了半天也没推出来,
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![有这样一个递推公式:2A(n+1)=An+n+3,又告诉A1=2,我想知道由上面的式子怎样推出{An}的通项公式:An=n+1 我自己做了半天也没推出来,](/uploads/image/z/400268-20-8.jpg?t=%E6%9C%89%E8%BF%99%E6%A0%B7%E4%B8%80%E4%B8%AA%E9%80%92%E6%8E%A8%E5%85%AC%E5%BC%8F%EF%BC%9A2A%28n%2B1%29%3DAn%2Bn%2B3%2C%E5%8F%88%E5%91%8A%E8%AF%89A1%3D2%2C%E6%88%91%E6%83%B3%E7%9F%A5%E9%81%93%E7%94%B1%E4%B8%8A%E9%9D%A2%E7%9A%84%E5%BC%8F%E5%AD%90%E6%80%8E%E6%A0%B7%E6%8E%A8%E5%87%BA%7BAn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%9AAn%3Dn%2B1+%E6%88%91%E8%87%AA%E5%B7%B1%E5%81%9A%E4%BA%86%E5%8D%8A%E5%A4%A9%E4%B9%9F%E6%B2%A1%E6%8E%A8%E5%87%BA%E6%9D%A5%2C)
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